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15p^2-27p-6=0
a = 15; b = -27; c = -6;
Δ = b2-4ac
Δ = -272-4·15·(-6)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-33}{2*15}=\frac{-6}{30} =-1/5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+33}{2*15}=\frac{60}{30} =2 $
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